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corrected some pages
Several small mistakes/errors were corrected in several proofs/definitions.
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D/cdf.md

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@@ -33,6 +33,7 @@ $$ \label{eq:cdf}
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F_X(x) = \mathrm{Pr}(X \leq x) \; .
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$$
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<br>
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1) Let $X$ be a discrete [random variable](/D/rvar) with possible outcomes $\mathcal{X}$ and the [probability mass function](/D/pmf) $f_X(x)$. Then, the function $F_X(x): \mathbb{R} \to [0,1]$ with
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$$ \label{eq:cdf-disc}

P/kl-nonneg2.md

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where $a_1, \ldots, a_n$ and $b_1, \ldots, b_n$ be non-negative real numbers and $a = \sum_{i=1}^{n} a_i$ and $b = \sum_{i=1}^{n} b_i$. Because $p(x)$ and $q(x)$ are [probability mass functions](/D/pmf), such that
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\begin{equation} \label{eq:p-q-pmf}
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$$ \label{eq:p-q-pmf}
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\begin{split}
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p(x) \geq 0, \quad \sum_{x \in \mathcal{X}} p(x) &= 1 \quad \text{and} \\
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q(x) \geq 0, \quad \sum_{x \in \mathcal{X}} q(x) &= 1 \; ,
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\end{split}
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\end{equation}
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$$
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theorem \eqref{eq:KL-nonneg} is simply a special case of \eqref{eq:logsum-ineq}, i.e.
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P/momcent-1st.md

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Due to the [linearity of the expected value](/P/mean-lin) and by plugging in $\mu = \mathrm{E}(X)$, we have
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\begin{equation} \label{eq:momcent-1st-qed}
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$$ \label{eq:momcent-1st-qed}
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\begin{split}
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\mu_1 &= \mathrm{E}\left[ X-\mu \right] \\
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&= \mathrm{E}(X) - \mu \\
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&= \mathrm{E}(X) - \mathrm{E}(X) \\
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&= 0 \; .
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\end{split}
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\end{equation}
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$$

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