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username: "tomfaulkenberry"
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**Theorem:** Let $X$ be a positive [random variable](/D/rvar) following a [Wald distribution](/D/wald):
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$$ \label{eq:wald}
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X \sim \mathrm{Wald}(\gamma, \alpha) \; .
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$$
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Then, the [mean or expected value](/D/mean) of $X$ is
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$$ \label{eq:wald-mean}
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\mathrm{E}(X) = \frac{\alpha}{\gamma} \; .
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$$
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**Proof:** The mean or expected value $\mathrm{E}(X)$ is the first [moment](/D/mom) of $X$, so we can use the [moment-generating function of the Wald distribution](/P/wald-mgf) to calculate
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**Proof:** The mean or expected value $\mathrm{E}(X)$ is the first [moment](/D/mom) of $X$, so [we can use](/P/mom-mgf) the [moment-generating function of the Wald distribution](/P/wald-mgf) to calculate
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$$ \label{eq:wald-moment}
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\mathrm{E}(X) = M_X'(0) \; .
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$$
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First we differentiate $M_X(t) = \exp\left[\alpha \gamma - \sqrt{\alpha^2(\gamma^2-2t)}\right]$ with respect to $t$. Using the chain rule gives
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