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| 1 | +--- |
| 2 | +layout: proof |
| 3 | +mathjax: true |
| 4 | + |
| 5 | +author: "Joram Soch" |
| 6 | +affiliation: "BCCN Berlin" |
| 7 | +e_mail: "joram.soch@bccn-berlin.de" |
| 8 | +date: 2024-11-08 10:46:00 |
| 9 | + |
| 10 | +title: "Moment-generating function of a sum of independent random variables" |
| 11 | +chapter: "General Theorems" |
| 12 | +section: "Probability theory" |
| 13 | +topic: "Other probability functions" |
| 14 | +theorem: "Moment-generating function of sum of independents" |
| 15 | + |
| 16 | +sources: |
| 17 | + - authors: "Probability Fact" |
| 18 | + year: 2021 |
| 19 | + title: "If X and Y are independent, the moment generating function (MGF)" |
| 20 | + in: "X" |
| 21 | + pages: "retrieved on 2024-11-08" |
| 22 | + url: "https://x.com/ProbFact/status/1468264616706859016" |
| 23 | + |
| 24 | +proof_id: "P478" |
| 25 | +shortcut: "mgf-sumind" |
| 26 | +username: "JoramSoch" |
| 27 | +--- |
| 28 | + |
| 29 | + |
| 30 | +**Theorem:** Let $X$ and $Y$ be two [independent](/D/ind) [random variables](/D/rvar) and let $Z = X + Y$. Then, the [moment-generating function](/D/mgf) of $Z$ is given by |
| 31 | + |
| 32 | +$$ \label{eq:mgf-sumind} |
| 33 | +M_Z(t) = M_X(t) \cdot M_Y(t) |
| 34 | +$$ |
| 35 | + |
| 36 | +where $M_X(t)$, $M_Y(t)$ and $M_Z(t)$ are the [moment-generating functions](/D/mgf) of $X$, $Y$ and $Z$. |
| 37 | + |
| 38 | + |
| 39 | +**Proof:** The [moment-generating function of a random variable](/D/mgf) $X$ is |
| 40 | + |
| 41 | +$$ \label{eq:mfg} |
| 42 | +M_X(t) = \mathrm{E} \left( \exp \left[ t X \right] \right) |
| 43 | +$$ |
| 44 | + |
| 45 | +and therefore the moment-generating function of the sum $Z$ is given by |
| 46 | + |
| 47 | +$$ \label{eq:mgf-sumind-s1} |
| 48 | +\begin{split} |
| 49 | +M_Z(t) |
| 50 | +&= \mathrm{E} \left( \exp \left[ t Z \right] \right) \\ |
| 51 | +&= \mathrm{E} \left( \exp \left[ t (X + Y) \right] \right) \\ |
| 52 | +&= \mathrm{E} \left( \exp \left[ t X \right] \cdot \exp \left[ t Y \right] \right) \; . |
| 53 | +\end{split} |
| 54 | +$$ |
| 55 | + |
| 56 | +Because the [expected value is multiplicative for independent random variables](/P/mean-mult), we have |
| 57 | + |
| 58 | +$$ \label{eq:mgf-sumind-s2} |
| 59 | +\begin{split} |
| 60 | +M_Z(t) |
| 61 | +&= \mathrm{E} \left( \exp \left[ t X \right] \right) \cdot \mathrm{E} \left( \exp \left[ t Y \right] \right) \\ |
| 62 | +&= M_X(t) \cdot M_Y(t) \; . |
| 63 | +\end{split} |
| 64 | +$$ |
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