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addd proof "mgf-sumind"
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---
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layout: proof
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mathjax: true
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author: "Joram Soch"
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affiliation: "BCCN Berlin"
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e_mail: "joram.soch@bccn-berlin.de"
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date: 2024-11-08 10:46:00
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title: "Moment-generating function of a sum of independent random variables"
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chapter: "General Theorems"
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section: "Probability theory"
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topic: "Other probability functions"
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theorem: "Moment-generating function of sum of independents"
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sources:
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- authors: "Probability Fact"
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year: 2021
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title: "If X and Y are independent, the moment generating function (MGF)"
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in: "X"
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pages: "retrieved on 2024-11-08"
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url: "https://x.com/ProbFact/status/1468264616706859016"
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proof_id: "P478"
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shortcut: "mgf-sumind"
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username: "JoramSoch"
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---
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**Theorem:** Let $X$ and $Y$ be two [independent](/D/ind) [random variables](/D/rvar) and let $Z = X + Y$. Then, the [moment-generating function](/D/mgf) of $Z$ is given by
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$$ \label{eq:mgf-sumind}
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M_Z(t) = M_X(t) \cdot M_Y(t)
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$$
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where $M_X(t)$, $M_Y(t)$ and $M_Z(t)$ are the [moment-generating functions](/D/mgf) of $X$, $Y$ and $Z$.
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**Proof:** The [moment-generating function of a random variable](/D/mgf) $X$ is
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$$ \label{eq:mfg}
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M_X(t) = \mathrm{E} \left( \exp \left[ t X \right] \right)
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$$
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and therefore the moment-generating function of the sum $Z$ is given by
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$$ \label{eq:mgf-sumind-s1}
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\begin{split}
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M_Z(t)
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&= \mathrm{E} \left( \exp \left[ t Z \right] \right) \\
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&= \mathrm{E} \left( \exp \left[ t (X + Y) \right] \right) \\
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&= \mathrm{E} \left( \exp \left[ t X \right] \cdot \exp \left[ t Y \right] \right) \; .
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\end{split}
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$$
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Because the [expected value is multiplicative for independent random variables](/P/mean-mult), we have
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$$ \label{eq:mgf-sumind-s2}
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\begin{split}
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M_Z(t)
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&= \mathrm{E} \left( \exp \left[ t X \right] \right) \cdot \mathrm{E} \left( \exp \left[ t Y \right] \right) \\
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&= M_X(t) \cdot M_Y(t) \; .
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\end{split}
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$$

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