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---
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layout: proof
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mathjax: true
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author: "Joram Soch"
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affiliation: "BCCN Berlin"
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e_mail: "joram.soch@bccn-berlin.de"
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date: 2024-10-11 11:52:29
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title: "Marginally normal does not imply jointly normal"
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chapter: "Probability Distributions"
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section: "Univariate continuous distributions"
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topic: "Normal distribution"
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theorem: "Marginally normal does not imply jointly normal"
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sources:
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- authors: "Wikipedia"
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year: 2024
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title: "Misconceptions about the normal distribution"
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in: "Wikipedia, the free encyclopedia"
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pages: "retrieved on 2024-10-11"
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url: "https://en.wikipedia.org/wiki/Misconceptions_about_the_normal_distribution#A_symmetric_example"
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proof_id: "P474"
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shortcut: "norm-margjoint"
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username: "JoramSoch"
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---
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**Theorem:** Consider two [random variables](/D/rvar) $X$ and $Y$. If the [marginal distribution](/D/dist-marg) of each of them is a [normal distribution](/D/norm), then the [joint distribution](/D/dist-joint) $X$ and $Y$ is not necessarily a [(multivariate) normal distribution](/D/mvn).
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**Proof:** Consider [the example used to show that normally distributed and uncorrelated does not imply independent](/P/norm-corrind). This is characterized by the [random variables](/D/rvar)
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$$ \label{eq:V-W}
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\begin{split}
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V &\sim \mathrm{Bern}\left( \frac{1}{2} \right) \\
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W &= 2V-1 \; .
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\end{split}
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$$
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and
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$$ \label{eq:X-Y}
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\begin{split}
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X &\sim \mathcal{N}(0,1) \\
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Y &= WX \; .
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\end{split}
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$$
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Under these conditions, [it can be shown that](/P/norm-corrind)
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$$ \label{eq:X-Y-dist}
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X \sim \mathcal{N}(0,1)
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\quad \text{and} \quad
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Y \sim \mathcal{N}(0,1) \; .
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$$
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The [linear transformation theorem for the multivariate normal distribution](/P/mvn-ltt)
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$$ \label{eq:mvn-ltt}
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x \sim \mathcal{N}(\mu, \Sigma) \quad \Rightarrow \quad y = Ax + b \sim \mathcal{N}(A\mu + b, A \Sigma A^\mathrm{T})
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$$
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implies that, for [bivariate normal random variables](/D/bvn) $X_1$ and $X_2$,
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$$ \label{eq:bvn}
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\left[ \begin{matrix} X_1 \\ X_2 \end{matrix} \right] \sim
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\mathcal{N}\left(
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\left[ \begin{matrix} \mu_1 \\ \mu_2 \end{matrix} \right],
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\left[ \begin{matrix} \sigma_1^2 & \sigma_{12} \\ \sigma_{12} & \sigma_2^2 \end{matrix} \right]
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\right) \; .
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$$
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any linear combination of $X_1$ and $X_2$ with non-zero coefficients
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$$ \label{eq:bvn-Z}
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Z = a X_1 + b X_2, \; a \neq 0, \; b \neq 0
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$$
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[follows a univariate normal distribution](/P/bvn-lincomb):
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$$ \label{eq:bvn-lincomb}
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Z \sim \mathcal{N}\left( a \mu_1 + b \mu_2, a^2 \sigma_1^2 + 2 a b \sigma_{12} + b^2 + \sigma_2^2 \right) \; .
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$$
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Consider the sum of $X$ and $Y$ defined by \eqref{eq:X-Y}:
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$$ \label{eq:Z}
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Z = X + Y = a X + b Y
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\quad \text{with} \quad
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a = b = 1 \; .
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$$
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If $X$ and $Y$ were [bivariate normally distributed](/D/bvn), then this sum should be [univariate normally distributed](/D/norm). However, this sum cannot be normally distributed, since
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$$ \label{eq:Z-dist}
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\mathrm{Pr}(X + Y = 0) = \frac{1}{2}
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\quad \text{and} \quad
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\mathrm{Pr}(X + Y = 2X) = \frac{1}{2} \; ,
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$$
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because
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$$ \label{eq:Y-dist}
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Y = \left\{
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\begin{array}{rl}
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X \; , & \text{with probability} \; 1/2 \\
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-X \; , & \text{with probability} \; 1/2
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\end{array}
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\right. \; .
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$$
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Thus, $X$ and $Y$ are not following a [bivariate normal distribution](/D/bvn). Therefore, $X$ and $Y$ defined by \eqref{eq:X-Y} and \eqref{eq:V-W} constitute an example for two [random variables](/D/rvar) that are [marginally normal](/D/norm), but not [jointly normal](/D/mvn).

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