@@ -1494,9 +1494,9 @@ \subsubsection{Unbreakable bonds}
14941494\includegraphics [width=\linewidth ]{CNT-unbreakable-length-energy}
14951495\caption {a) Evolution of the length $ L_\text {cnt}$ of the CNT with time,
14961496as simulated during \hyperref [carbon-nanotube-label]{Tutorial 2}.
1497- The CNT starts deforming at $ t = 5 \, \text {ps}$ . b) Evolution of the total
1498- energy $ E_\text {tot}$ of the system with time $ t $ . Here, the potential is OPLS-AA,
1499- and the CNT is unbreakable.}
1497+ The CNT starts deforming at $ t = 5 \, \text {ps}$ , and $ L_ \text {cnt-0} $ is the
1498+ CNT initial length. b) Evolution of the total energy $ E_\text {tot}$ of the system
1499+ with time $ t $ . Here, the potential is OPLS-AA, and the CNT is unbreakable.}
15001500\label {fig:CNT-unbreakable-LE }
15011501\end {figure }
15021502
@@ -1537,7 +1537,7 @@ \subsubsection{Unbreakable bonds}
15371537\includegraphics [width=0.55\linewidth ]{CNT-unbreakable-stress-strain}
15381538\caption {Stress applied on the CNT during deformation, $ F_\text {cnt}/A_\text {cnt}$ ,
15391539where $ F_\text {cnt}$ is the force and $ A_\text {cnt}$ the CNT surface area,
1540- as a function of the strain, $ (L_\text {cnt}-L_\text {cnt-0}/L_\text {cnt-0})$ , where
1540+ as a function of the strain, $ \Delta L_ \text {cnt} = (L_\text {cnt}-L_\text {cnt-0}/L_\text {cnt-0})$ , where
15411541$ L_\text {cnt}$ is the CNT length and $ L_\text {cnt-0}$ the CNT initial length,
15421542as simulated during \hyperref [carbon-nanotube-label]{Tutorial 2}.
15431543Here, the potential is OPLS-AA, and the CNT is unbreakable.}
@@ -1662,7 +1662,7 @@ \subsubsection{Breakable bonds}
16621662\caption {a) Evolution of the total energy $ E_\text {tot}$ of the CNT with time $ t$ .
16631663b) Stress applied on the CNT during deformation, $ F_\text {cnt}/A_\text {cnt}$ ,
16641664where $ F_\text {cnt}$ is the force and $ A_\text {cnt}$ the CNT surface area,
1665- as a function of the strain, $ (L_\text {cnt}-L_\text {cnt-0}/L_\text {cnt-0})$ , where
1665+ as a function of the strain, $ \Delta L_ \text {cnt} = (L_\text {cnt}-L_\text {cnt-0}/L_\text {cnt-0})$ , where
16661666$ L_\text {cnt}$ is the CNT length and $ L_\text {cnt-0}$ the CNT initial length,
16671667as simulated during \hyperref [carbon-nanotube-label]{Tutorial 2}.
16681668Here, the potential is AIREBO, and the CNT is breakable.}
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